Решить уравнение log (127+x³)-3log(x+1)=0

log(127+x³)-3*log(x+1)=0 ОДЗ: [latex] \left \{ {{127+ x^{3} \ \textgreater \ 0} \atop {x+1\ \textgreater \ 0}} \right. , \left \{ {{ x^{3}\ \textgreater \ -127 } \atop {x\ \textgreater \ -1}} \right. , \left \{ {{x\ \textgreater \ \sqrt[3]{-127} } \atop {x\ \textgreater \ -1}} \right. [/latex] x>-1. x∈(-1;∞) log(127+x³)=3*log(x+1) log(127+x³)=log(x+1)³ 127+x³=(x+1)³ 127+x³=x³+3x²+3x+1 3x²+3x-126=0 |:3 x²+x-42=0 D=169 x₁=-7, x₂=6 -7∉(-1;∞). => x=-7 посторонний корень ответ: x=6