Решить уравнение:[latex] (8x+3)^{2} [/latex] - [latex] x^{4} [/latex] = 8[latex] x^{2} [/latex] + 16

[latex] (8x+3)^{2} - x^{4} = 8 x^{2} + 16 \\\ (8x+3)^{2} = x^{4} + 8 x^{2} + 16 \\\ (8x+3)^{2} -( x^2 +4)^2=0 \\\ (8x+3 -( x^2 +4)) (8x+3 +( x^2 +4))=0 \\\ x^2-8x+1=0 \\\ D_1=16-1=15 \\\ x=4\pm \sqrt{15} \\\ x^2 +8x+7=0 \\\ D_1=16-7=9 \\\ x=-7 \\\ x=-1[/latex] Ответ: [latex]-1, -7, 4\pm \sqrt{15} [/latex]