Решить уравнения.1) (3-4sin x) (3+4 cos x)=02) (tg x+3((tg+1)=03) sin 2x=3 sin x cos(квадрат)x4) sin 4x = sin 2x

1) (3-4sinx)(3+4cosx)=0 sinx=3/4 x=(-1)^k*arcsin3/4+πk cosx=-3/4 x=±arccos(-3/4)+2πn 2) (tgx+3)(tgx+1)=0 tgx+3=0 tgx=-3 x=-arctg3+πn, n € Z tgx+1=0 tgx=-1 x=arctg(-1)+πn x=-π/4+πn, n € Z. 3)sin2x=3sinx*cos²x 2sinx*cosx-3sinx*cos²x=0 sinx*cosx(2-3cosx)=0 sinx=0 x=πn, n € Z cosx=0 x=π/2+πn, n € Z cosx=2/3 x=±arccos2/3+πn, n € Z 4)sin4x-sin2x=0 2sin2x*cos2x-sin2x=0 sin2x(2cos2x-1)=0 sin2x=0 2x=πk, k € Z x=πk/2, k € Z cos2x=1/2 2x=±π/3+2πn, n € Z x=±π/6+πn, n € Z