Решите 1,2,3 хотябы!

1)[latex] \frac{3x-1}{4}- \frac{2x+3}{3}=1 [/latex] [latex] \frac{3(3x-1)-4(2x+3)}{12} =1[/latex] [latex] \frac{9x-3-8x-12}{12}=1 [/latex] [latex] \frac{x-15}{12} =1[/latex] [latex] \frac{x-15-12}{12} =0[/latex] [latex] \frac{x-27}{12}=0 [/latex] x=27 2)[latex] \frac{1}{2}x-1= \frac{1}{3}(x+ \frac{3}{4}) [/latex]    [latex] \frac{1}{2}x- \frac{1}{3}x=1+ \frac{3}{12} [/latex]      [latex] \frac{1}{6}x= \frac{15}{12} [/latex]    [latex] x= \frac{15}{2}=7,5 [/latex] 3)[latex] \frac{1}{3}x-1= \frac{1}{4(x+ \frac{4}{5}) } [/latex]    [latex] \frac{1}{3}x-1= \frac{1}{4}x+ \frac{4}{20} [/latex]    [latex] \frac{1}{3}x- \frac{1}{4}x=1+ \frac{1}{5} [/latex]    [latex] \frac{1}{12}x= \frac{6}{5} [/latex]    [latex] x= \frac{72}{5}=14,4 [/latex]