Решите алгебру пожалуйста!!!!! logx^2(x+2)⩽1

Метод рационализации: [latex]log_{x^2}(x+2) \leq 1\\\\ODZ: \left \{ {{x+2\ \textgreater \ 0} \atop {x^2\ \textgreater \ 0,x^2\ne 1}} \right. \; \left \{ {{x\ \textgreater \ -2} \atop {x\ne 0,x\ne \pm 1}} \right. \; \; \to \\\\x\in(-2,-1)\cup (-1,0)\cup (0,1)\cup (1,+\infty )\\\\(x^2-1)(x+2-x^2) \leq 0\\\\-(x-1)(x+1)(x^2-x-2) \leq 0\\\\(x-1)(x+1)(x+1)(x-2) \geq 0\\\\(x+1)^2(x-1)(x-2) \geq 0\\\\+++(-1)+++(1)---(2)+++\\\\x\in (-2 ,-1)U(-1,0)U(0,1)U[\, 2,+\infty )[/latex]