Решите log3(x^2-3x-5)=log3(7-2x)

[latex]log_3(x^2-3x-5)=log_3(7-2x)\; ;\; \; ODZ:\; \; \left \{ {{x^2-3x-5\ \textgreater \ 0} \atop {7-2x\ \textgreater \ 0}} \right. \\\\x^2-3x-5=7-2x\\\\x^2-x-12=0\\\\x_1=-3,\; \; x_2=4\\\\(-3)^2-3\cdot (-3)-5=13\ \textgreater \ 0,\; \; 7-2(-3)=13\ \textgreater \ 0\\\\4^2-3\cdot 4-5=-1\ \textless \ 0\; \; \to \; \; x_2=4\notin ODZ\\\\Otvet:\; \ x=-3\; .[/latex]