Решите неравенства: (x-2)(x+5) больше 0 x^2-16 меньше 0

[latex]1)\quad (x-2)(x+5)\ \textgreater \ 0\\\\+++(-5)---(2)+++\\\\x\in (-\infty ,-5)\cup (2,+\infty )\\\\2)\quad x^2-16\ \textless \ 0\\\\(x-4)(x+4)\ \textless \ 0\\\\+++(-4)---(4)+++\\\\x\in (-4,4)[/latex]