Решите неравенство (2,5)^2x+1 больше 4/25

[latex]2.5=\frac{25}{10}=\frac{25:5}{10:2}=\frac{5}{2}[/latex] [latex]\frac{4}{25}=\frac{2*2}{5*5}=(\frac{2}{5})^2=(\frac{5}{2})^{-2}[/latex] -------------------------------------------- [latex](2.5)^{2x+1}>\frac{4}{25}[/latex] [latex](\frac{5}{2})^{2x+1}>(\frac{5}{2})^{-2}[/latex] [latex]\frac{5}{2}>1[/latex] [latex]2x+1>-2[/latex] [latex]2x>-2-1[/latex] [latex]2x>-3[/latex] [latex]x>-3:2[/latex] [latex]>-1.5[/latex] x є [latex](-1.5;+\infty)[/latex]