Решите неравенство: 2cos (3π/2 + 3x) ≤ -√3

[latex]2cos( \frac{3\pi }{2} + 3x ) \leq - \sqrt{3} 2sin3x \leq - \sqrt{3} sin3x \leq - \frac{\sqrt3}{2} 3x \leq (-1)^{k+1}arcsin \frac{\sqrt3}{2} + \pi*k, k belons to Z 3x \leq (-1)^{k+1}* \frac{\pi}{3} + \pi*k, k belongs to Z x \leq (-1)^{k+1}* \frac{\pi}{9} + \frac{\pi*k}{3}, k belongs to Z [/latex]