Решите неравенство 2x²-6x+5/2x-3≤1

[latex] \frac{2x^2-6x+5}{2x-3} \leq 1\\\\ \frac{2x^2-6x+5}{2x-3}-1 \leq 0\\\\ \frac{2x^2-8x+8}{2x-3} \leq 0 [/latex] ОДЗ: [latex]2x-3 \neq 0\\ 2x \neq 3\\ x \neq \frac{3}{2} [/latex] [latex]2x^2-8x+8 \leq 0 \ |:2\\ x^2-4x+4 \leq 0\\ (x-2)^2 \leq 0\\ x-2 \leq 0\\ x \leq 2[/latex] ___-___[latex]\frac{3}{2} [/latex]___+___[latex]2[/latex]___+___ Ответ: [latex]x\in (-\infty; \frac{3}{2}) [/latex]