Решите неравенство [latex]log _{2} (5-x)*log _{2} (x+1) \leq log _{2} ((x^2-4x-5)^2/16)[/latex]

[latex]log_2(5-x)*log_2(x+1) \geq log_2((x-5)^2(x+1)^2)-4 \\ log_2(5-x)*log_2(x+1)-2log_2(5-x)-2log_2(x+1)+4 \leq 0 \\ log_2(5-x)[log_2(x+1)-2]-2[log_2(x+1)-2] \leq 0 \\ (log_2(x+1)-2)[log_2(5-x)-2] \leq 0 \\ Zeros: \\ 1) log_2(x+1)=2 \\ x+1=4 =\ \textgreater \ x=3; \\ \\ \\ 2) log_2(5-x)=2 \\ 5-x=4 =\ \textgreater \ x=1. \\ \\ \\ \\ 5-x\ \textgreater \ 0 =\ \textgreater \ x\ \textless \ 5; \\ x+1\ \textgreater \ 0 =\ \textgreater \ x\ \textgreater \ -1 \\ \\ x \in (-1;1] \cup [3;5) [/latex]