Решите неравенство log1/3 (12-x) меньше 2

[latex]log_{1/3}(12-x)\ \textless \ 2\\OD3:\\12-x\ \textgreater \ 0\\x\ \textless \ 12\\\\log_{1/3}(12-x)\ \textless \ log_{1/3} \frac{1}{9}\\0\ \textless \ \frac{1}{3} \ \textless \ 1\\\\12-x\ \textgreater \ \frac{1}{9} \\\\x\ \textless \ 12- \frac{1}{9}\\\\x\ \textless \ 11 \frac{8}{9}\\\\x\in (-\infty;11 \frac{8}{9}) [/latex]