Решите неравенство sqrt(x+2) больше sqrt(4-x)

[latex]\sqrt{x+2}\ \textgreater \ \sqrt{4-x}\; \; \; \Leftrightarrow \; \; \; \left \{ {{x+2\ \textgreater \ 4-x} \atop {4-x \geq 0}} \right. \; ,\; \left \{ {{2x\ \textgreater \ 2} \atop {x \leq 4}} \right. \; ,\; \left \{ {{x\ \textgreater \ 1} \atop {x \leq 4}} \right. \\\\x\in (1,4\, ][/latex]