Решите пожалуйста по теме способом группировки: bx-by+px-py, 3a+ba+3m+bm, 2a+pk+ka+2p, 3x+mn+nx+3m, xy+xb-4y-4b, ma+mb-5a-5b.

ответ b (x-y)+p (x-y)=(x-y)(b+p) 3 (a+m)+b (a+m)=(a+m)(3+b) 2 (a+p)+k (a+p)=(2+k)(a+p) 3 (x+m)+n (m+x)=(x+m)(3+n) x (y+b)-4 (y+b)=(y+b)(x-4) m (a+b)-5 (a+b)=(a+b)(m-5)

1. bx-by+px-py = (bx-by) + (px-py) = b(x-y) + p(x-y) = (b + p)(x - y) 2. 3a+ba+3m+bm = (3a + 3m) + (ba + bm) = 3(a + m) + b(a + m) = (3 + b)(a + m) 3. 2a+pk+ka+2p = (2a+2p) + (ak+pk) = 2(a+p) + k(a+p) = (2+k)(a+p) 4. 3x+mn+nx+3m = (3x+3m) + (nx+mn) = 3(x+m) + n(x+m) = (3+n)(x+m) 5. xy+xb-4y-4b = (xy-4y) + (xb-4b) = y(x-4) + b(x-4) = (y+b)(x-4)  6. ma+mb-5a-5b = (ma-5a) + (mb-5b) = a(m-5) + b(m-5) =  (a+b)(m-5)