Решите пример [latex] \frac{4}{12} + (1 \frac{3}{4} - \frac{1}{12} ) - \frac{5}{14} + 1 \frac{2}{3} [/latex]

[latex] \frac{4}{12}+ \frac{7}{4}- \frac{1}{12}- \frac{5}{14}+\frac{5}{3}=2+ \frac{5}{3}- \frac{5}{14}= \frac{84-40+140}{42}= \frac{184}{42}=4 \frac{18}{42} [/latex]