Решите пример по фотографии

[latex]\displaystyle \left(9\frac{1}{4} -8\frac{2}{3}\right)\cdot1\frac{5}{7}+\left(4\frac{2}{9} -2\frac{5}{6}\right):1\frac{1}{9}= \\ \left(1+\frac{1}{4} -\frac{2}{3}\right)\cdot\frac{12}{7}+\left(2+\frac{2}{9} -\frac{5}{6}\right):\frac{10}{9}= \\ \left(1+\frac{1\cdot3-2\cdot4}{12}\right)\cdot\frac{12}{7}+\left(2+\frac{2\cdot2-5\cdot3}{9}\right)\cdot\frac{9}{10}= \\ \left(1-\frac{5}{12}\right)\cdot\frac{12}{7}+\left(2-\frac{11}{18}\right)\cdot\frac{9}{10}=[/latex][latex]\displaystyle \left( \frac{12}{12} -\frac{5}{12}\right)\cdot\frac{12}{7}+\left( \frac{36}{18} -\frac{11}{18}\right)\cdot\frac{9}{10}= \frac{7}{12}\cdot \frac{12}{7}+ \frac{25}{18}\cdot \frac{9}{10}= \\ 1+\frac{5\cdot5}{2\cdot9}\cdot \frac{9}{2\cdot5}=1+ \frac{5}{2\cdot2}=1+ \frac{5}{4}=1+1 \frac{1}{4}=2 \frac{1}{4} [/latex]

[latex](9 \frac{1}{4} - 8 \frac{2}{3} ) * 1 \frac{5 }{7} +(4 \frac{2}{9} - 2 \frac{5}{6} ) :1 \frac{1}{9} = \frac{7 }{12} * \frac{12}{7} + \frac{25}{18} * \frac{9}{10} = 1 + \frac{5}{4} =2,25[/latex]