Решите пункт б плиз.

[latex] \left [ {{x(x+1) \leq 0} \atop {3x-9\ \textgreater \ 0}} \right. \; \; \left [ {{x\in [-1,0\; ]} \atop {3x\ \textgreater \ 9}} \right. \; \; \left [ {{x\in [-1,0\; ]} \atop {x\ \textgreater \ 3}} \right. \; \; \left [ {{x\in [-1,0\, ]} \atop {x\in (3,+\infty )}} \right. \; \Rightarrow \\\\ x\in [-1,0\, ]\cup (3,+\infty )\\\\\\x(x+1) \leq 0\quad +++[-1\, ]---[\, 0\, ]+++\quad x\in [-1,0\, ][/latex]