Помогите решить !!!!!!!!!!!!!!!!1!!1!111.Пж

[latex] \frac{ b^{2} }{ b^{2} -6ab} : \frac{b}{ b^{2} -36ab} = \frac{ b^{2}( b^{2}-36ab) }{b( b^{2}-6ab) } = \frac{(b-6a)(b+6a)}{b(b-6a)} =[/latex] [latex]= \frac{b+6a}{b} [/latex] [latex] \frac{(7+12 \sqrt{3})+6(11-2 \sqrt{3}) }{7+12 \sqrt{3} } = \frac{7+12 \sqrt{3}+66-12 \sqrt{3} }{7+12 \sqrt{3} } = \frac{73}{7+ 12 \sqrt{3} } [/latex]