Решите систему уравнений (х-8)(у-6)=0 У-2/х+у-10=4

[latex] \left \{ {{(x-8)(y-6)=0} \atop {y-2=4x+4y-40}} \right. [/latex] [latex]\left \{ {{(x-8)(y-6)=0} \atop {y= \frac{38-4x}{3} }} \right.[/latex] [latex](x-8)( \frac{38-4x}{3} -6)=0[/latex] [latex](x-8)( \frac{20-4x}{3} )=0[/latex] [latex]x-8=0[/latex] и[latex] \frac{20-4x}{3} =0[/latex] [latex]x=8[/latex] и [latex]x=5[/latex] 1.[latex] \left \{ {{x=8} \atop { \frac{y-2}{8+y-10}=4 }} \right. [/latex] [latex]\left \{ {{x=8} \atop { \frac{y-2}{y-2}=3 }} \right. (1 \neq 3) [/latex] - не уд. 2.[latex] \left \{ {{x=5} \atop { \frac{y-2}{5+y-10}=4 }} \right. [/latex] [latex] \left \{ {{x=5} \atop {y=6}} \right. [/latex]