Решите систему уравнений х2-2ху=7,х-3у=-2

x^2 - 2xy = 7 x = 3y - 2 (3y - 2)^2 - 2*(3y-2)*y = 7;  9y^2 - 12y + 4 - 6y^2 + 4y = 7 3Y^2 - 8y - 3 = 0 D = 64 - 4 * 3 * (-3) = 64 + 36 = 100 Y1 = (8 + 10): 6 =3 y2 = (8 - 10) : 6 = - 1/3 ///////////////////////////////////// x1 = 3* y1 - 2 = 3 * 3 - 2 = 7 x2 = 3 * y2 - 2 = 3 * (-1\3) - 2 = -1 - 2 = - 3 ОТВЕТ: X 1 = 7  y1 = 3              X 2 = - 3  y2 = - 3