Решите систему уравнений {х^2+у=14 {х-2у=-1

[latex] \left \{ {{y=14-x^2} \atop {x-28+2x^2+1=0}} \right. \\ \left \{ {{y=14-x^2} \atop {2x^2+x-27=0}} \right. \\ \left \{ {{y=14-x^2} \atop {x_{1} =- \frac{3}{2} };x x_{2}=2 } \right. \\ \left \{ {{y_{1} = \frac{47}{4};y_{2}=4 } \atop { x_{1} =- \frac{3}{2} };x_{2}=2} \right. [/latex]