Решите систему уравнений [latex]\left \{ {2x^2-xy-3y^2+x+y=6 \atop 2x^2-5xy+3y^2+x-y=2} \right. [/latex]  

[latex]\left \{ {{(x+y)(2x-3y)+(x+y)=6} \atop {(x-y)(2x-3y)+(x-y)=2}} \right.\\\ \left \{ {{(x+y)(2x-3y+1)=6} \atop {(x-y)(2x-3y+1)=2}} \right. \\\ \left \{ {{\frac{x+y}{x-y}=3} \atop {2x^2-5xy+3y^2+x-y=2}} \right. \\\ \left \{ {{x+y=3(x-y)} \atop {2x^2-5xy+3y^2+x-y=2}} \right.\\\ \left \{ {{x=2y} \atop {8y^2-10y^2+3y^2+2y-y=2}} \right.\\\ \left \{ {{x=2y} \atop {y^2+y-2=0}} \right.[/latex] [latex]\left \{ {{x=2y} \atop {y=1}} \right.[/latex] или [latex]\left \{ {{x=2y} \atop {y=-2}} \right.[/latex] [latex]\left \{ {{x=2} \atop {y=1}} \right.[/latex] или [latex]\left \{ {{x=-4} \atop {y=-2}} \right.[/latex] Ответ: (2; 1); (-4; -2)