Решите систему уравнений на листочке плиз

[latex]\left\{{{2x^2+4y^2=24,}\atop{4x^2+8y^2=24x}}\right.\left\{{{2x^2+4y^2=24,}\atop{4x^2+8y^2-24x=0}}\right.\left\{{{x^2+2y^2=12,}\atop{2x^2+4y^2-12x=0}}\right.\left\{{{-2x^2-4y^2=-24,}\atop{2x^2+4y^2-12x=0}}\right.\\-2x^2-4y^2+2x^2+4y^2-12x=-24+0\\-12x=-24\\x=2\\2y^2=12-x^2\\y^2=\frac{12-4}{2}\\y^2=4\\y=б2[/latex] Ответ: [latex](2;б2)[/latex]