Решите систему уравнений способом подстановки: 4x+3y=5 x-y=3 x-y=7 5x-3y=1 6x+5y=6 2x+y=-2

[latex]\left\{\begin{matrix} 4x &+ &3y &= &5 \\ x &- &y &= &3 \end{matrix}\right.\\\\ \left\{\begin{matrix} 4x &+ &3y &= &5 \\ x &= &3 &+ &y \end{matrix}\right.\\\\ 4(3+y)+3y=5\\ 12+4y+3y=5\\ 7y=-7\\ y=-1\\\\ x=3-1\\ x=2[/latex] Ответ: [latex](2;-1)[/latex] [latex]\left\{\begin{matrix} x &- &y &= &7 \\ 5x &- &3y &= &1 \end{matrix}\right.\\\\ \left\{\begin{matrix} x &= &7 &+ &y \\ 5x &- &3y &= &1 \end{matrix}\right.\\\\ 5\cdot(7+y)-3y=1\\ 35+5y-3y=1\\ 2y=-34\\ y=-17\\\\ x=7-17\\ x=-10[/latex] Ответ: [latex](-10;-17)[/latex] [latex]\left\{\begin{matrix} 6x&+ &5y &= &6 \\ 2x &+ &y &= &-2 \end{matrix}\right.\\\\ \left\{\begin{matrix} 6x&+ &5y &= &6 \\ y &= &-2 &-&2x \end{matrix}\right.\\\\ 6x+5(-2-2x)=6\\ 6x-10-10x=6\\ -4x=16\\ x=-4\\\\ y=-2-2\cdot(-4)\\ y=6[/latex] Ответ: [latex](-4;6)[/latex]