Решите уравнение 1. x(x-1)=02. (x+3)(x-2)=03. (2x-1/3)(3x+3)=0

1.x(x-1)=0 x=0 или x-1=0                x=1 2.(x+3)(x-2)=2 [latex] x^{2} -2x+3x-6=0[/latex] [latex] x^{2} +x-6=0[/latex] [latex]D= b^{2} -4ac= 1^{2} -4*1*(-6)=1+24=25[/latex] [latex] x_{1} = \frac{-1+5}{2} = \frac{4}{2} =2[/latex] [latex] x_{2}= \frac{-1-5}{2}= \frac{-6}{2} =-3[/latex] 3.(2x-1/3)(3x+3) [latex]6 x^{2} +6x-x-1=0[/latex] [latex]6 x^{2} +5x-1=0[/latex] D=25-4*6*(-1)=25+24=49 [latex] x_{1} = \frac{-5+7}{12}= \frac{2}{12} = \frac{1}{6} [/latex] [latex] x_{2} = \frac{-5-7}{12} = \frac{-12}{12} =-1[/latex]