Решите уравнение: 1)192:(5х-3)-7/9=10005/100052)(7х+16):11+8/12=19991/19991Пожалуйста помогите

1. [latex] \frac{192}{5x-3} - \frac{7}{9} =1\\ \frac{192}{5x-3} = \frac{16}{9} \\16(5x-3)=192*9/:16\\5x-3=108\\5x=111/:5\\x= \frac{111}{5} \\x=22,2[/latex] 2. [latex] \frac{7x+16}{11} + \frac{8}{12} =1\\ \frac{7x+16}{11} = \frac{1}{3} \\3(7x+16)=11\\21x+48=11\\21x=-37/:21\\x=-1 \frac{16}{21} [/latex]