Решите уравнение: 1)84а+25а+7=443 2)4(9+7х)+21=393

109a = 443 - 7 109a = 436 a = 436/109 a = 4 36 + 28x + 21 =393 28x = 393 - 57 28x = 336 x = 336/28 x = 12

1)  84а + 25а + 7 = 443        2) 4(9+7х) + 21 = 393109а = 443 - 7                          36 + 28х + 21 = 393 109а = 436                               28х + 57 = 393 а = 4                                         28х = 393 - 57                                                  28х = 336                                                      х = 12