Решите уравнение 2sin ( √x + Π/2 ) = √3

2sin ( √x + Π/2 ) = √3 sin ( √x + Π/2 )=√3/2 √x + Π/2=(-1)ⁿ(π/3)+πn,  n∈Z 1) √x + Π/2= (π/3)+2πn    √x =(π/3-π/2)+2πn   √x =(-π/6)+2πn    n=1,2,3,.... x =π²(-1/6+2n )²  n=1,2,3,.... 2)√x + Π/2= π-(π/3)+2πk  √x = π-π/2-(π/3)+2πk   √x = π/6+2πk   k=1,2,3,.... x=π²(1/6+2k )²     k=1,2,3,...