Решите уравнение 2x - x2( во второй степени) + 1 = 0

- x^2 + 2x + 1 = 0   /:(-1) x^2 - 2x - 1 = 0  D = 4 + 4 = 8 √D = 2√2 x1 = ( 2 +  2√2)/2 = 1 + √2; x2 = ( 2 - 2√2)/2 = 1 - √2;

[latex]2x-x^2+1=0\; |\cdot (-1)\\\\x^2-2x-1=0\\\\D=4+4=8\\\\x_1= \frac{2-\sqrt{8}}{2} = \frac{2-2\sqrt2}{2} =1-\sqrt2\; ,\; \; x_2=1+\sqrt2 [/latex] [latex]ili\\\\x^2-2x-1=0\\\\(x-1)^2-1-1=0\\\\(x-1)^2=2\\\\x-1=\pm \sqrt2\\\\x-1=-\sqrt2\; \; \; ili\quad x-1=\sqrt2\\\\x_1=1-\sqrt2\quad ili\quad x_2=1+\sqrt2[/latex]