Решите уравнение 36x^2-(3x-27)^2=0

[latex]36 x^{2} - (3x-27)^{2} =0 \\ 36 x^{2} -(9 x^{2} -162x+729)=0 \\ 36 x^{2} -9 x^{2} +162x-729=0 \\ 27 x^{2} +162x-729=0 \\ [/latex] D = 162² - 4*27*(- 729) = 26244 + 78732 = 104976 = 324² х₁ [latex] =\frac{-162+324}{2*27} = \frac{162}{54} =3[/latex] х₂[latex]= \frac{-162-324}{2*27} = - \frac{486}{54} = - 9[/latex] Ответ: 3 и - 9