Решите уравнение 4/(x+1)-x/(x-1) = (x^2-3)/(1-x^2)

[latex]\displaystyle \frac{4}{x+1}- \frac{x}{x-1} = \frac{x^2-3}{1-x^2} \\ \\ \frac{4}{x+1} - \frac{x}{x-1} = \frac{3-x^2}{1-x^2} [/latex] ОДЗ: [latex]x^2-1\ne 0;\,\,\,\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,\, x=\pm 1[/latex] Домножим оба части уравнения на [latex](x^2-1)[/latex] [latex]4(x-1)-x(x+1)=(3-x^2)\\ \\ 4x-4-x^2-x=3-x^2\\\\ 3x=7\\ \\ x= \dfrac{7}{3} [/latex] Ответ: [latex]\dfrac{7}{3}.[/latex]