Решите уравнение 6/х+5=4/3+х

[latex] \frac{6}{x} + 5 = \frac{4}{3 } + x [/latex] [latex] \frac{6+5x}{x} = \frac{4+3x}{3} [/latex] [latex] \frac{6+5x}{x} - \frac{4+3x}{3 } = 0[/latex] [latex] \frac{18+15x-4x- 3x^{2} }{3x} = 0 [/latex] [latex]x \neq 0 [/latex] [latex]18+15x -4x -3 x^{2} = -3 x^{2} +11x +18 = 0 [/latex] [latex]3 x^{2} - 11x - 18 = 0 [/latex] D= b*b - 4ac D= 121 + 216 = 337 [latex]x= \frac{-b+- \sqrt{D} }{2a} [/latex] [latex]x= \frac{11-+ \sqrt{337} }{6} [/latex]