Решите уравнение 6sin^2x=5sinxcosx-cos^2x

Решение 6sin^2x=5sinxcosx-cos^2x  6sin^2x - 5sinxcosx  + cos^2x = 0 делим на ²x ≠ 0 6tg²x - 5tgx + 1 = 0 tgx = t 6t² - 5t + 1 = 0 D = 25 - 4*6*1 = 1 t = (5-1)/12 t = 1/3 t = (5+1)/12 t = 1/2 1)  tgx = 1/3 x ₁= arctg(1/3) + πk, k ∈ Z 2)  tgx = 1/2 x₂ = arctg(1/2) + πn, n ∈Z