Решите уравнение х^2-4.5х/х-4=х-8/2х-8

[latex] \frac{x^2 -4,5x}{x-4} = \frac{x-8}{2x-8} [/latex] [latex] \frac{x^2 - 4,5x}{x-4} = \frac{x-8}{2(x-4)} [/latex] [latex] 2(x^2-4,5x) = {x-8}[/latex] [latex]2x^2 - 9x = x-8[/latex] [latex]2x^2 - 10x + 8 = 0 |:2[/latex] [latex]x^2-5x + 4 = 0[/latex] D = 25 - 16 = 9 x₁ = (5 + 3) / 2 = 4 x₂ = (5 - 3) / 2 = 1