Решите уравнение :sin(-x/2)=1/2 2cos(2x+pi/4)=-sqrt2ПОМОГИТЕ , УМОЛЯЮ

sin(-x/2)=1/2 -sinx/2=1/2 sinx/2=-1/2 x/2=(-1)^(n+1)π/6+πn, n∈Z x=(-1)^(n+1)π/3+2πn, n∈Z 2cos(2x+π/4)=-√2 cos(2x+π/4)=-√2/2 2x+π/4=+/-(π-π/4)+2πk, k∈Z 2x+π/4=+/-3π/4+2πk, k∈Z 2x=+/-3π/4-π/4+2πk, k∈Z 2x=3π/4-π/4+2πk=π/2+2πk, k∈Z      x1=π/4+πk, k∈Z 2x=-3π/-π/4+2πk=-π+2πk, k∈Z        x2=-π/2+πk, k∈Z