Решите уравнение sinx-√2/2=0

[latex]\displaystyle\sin x- \frac{ \sqrt{2} }{2}=0 [/latex] [latex]\displaystyle\sin x= \frac{ \sqrt{2} }{2} [/latex] [latex]\displaystyle x=(-1)^n\arcsin \frac{ \sqrt{2} }{2} +\pi n,n\in \mathbb Z[/latex] [latex]\displaystyle x=(-1)^n \frac{\pi}{4}+\pi n , n\in\mathbb Z [/latex]