Решите уравнение (x-0,25) + 3 1/12= 7 1/3

[latex]\displaystyle (x-0,25)+3 \frac{1}{2} =7 \frac{1}{3} [/latex] [latex]\displaystyle (x- \frac{25}{100})+3 \frac{1}{2} =7 \frac{1}{3}[/latex] [latex]\displaystyle x- \frac{25}{100}+ \frac{7}{2} = \frac{22}{3} [/latex] [latex]\displaystyle x= \frac{25}{100} - \frac{350}{100} + \frac{22}{3} \\\\x= -\frac{325}{100} + \frac{22}{3} \\\\x= -\frac{975}{300}+ \frac{2200}{300}= \frac{1225}{300}= \frac{49}{12} =4 \frac{1}{12}\\\\\boxed{x=4 \frac{1}{12} }[/latex]

ответ 1 целая и 3/4 я решил в уме