Решите уравнение (x-2)^2-9=0 СРОЧНО!!!

x²-4x+4-9=0 x²-4x-5=0 D=(-4)²-4*1*(-5)=16+20=36 x₁=(4+6)/2=10/2=5 x₂=(4-6)/2=-2/2=-1

[latex](x-2)^2-9=0\\\\(x-2)^2-3^2=0\qquad \quad [\; a^2-b^2=(a-b)(a+b)\; ]\\\\(x-2-3)(x-2+3)=0\\\\(x-5)(x+1)=0\\\\x-5=0\; \; \; \to \; \; \; x=5\\\\x+1=0\; \; \; \to \; \; \; x=-1[/latex]