Решите уравнение: y-3/5=(1+y/2)-(y+2/4)-1

(y-3)/5 = (1+y)/2 - (y+2)/4 - 1; (y-3)/5 = 2(1+y)/4 - (y+2)/4 - 1; (y-3)/5 = (2+2y-y-2)/4 - 1; (y-3)/5 = y/4 - 1; 1 = y/4 - (y-3)/5; 1= (5y- 4(y-3)) / 20; 1 = (5y - 4y +12) / 20; 1 = (y+12) / 20; y+12 = 20; y = 8. Проверка совпала.