Решите уравнение:4x^3-4x=0

4x³ - 4x = 0 4x·(x² - 1) = 0 4x·(x - 1)·(x + 1) = 0 x₁ = -1 x₂ = 0 x₃ = 1

[latex]x(4x^2-4)=0\\x_1=0;4x_2^2=4\\x_1=0;x_2^2=1\\x_1=0;x_2=1;x_3=-1[/latex]