Решите уравнения 1) х^2-49=0 2)25у^2-4=0 3)16х^2+25=0 4)(3х-5)^2-16=0

1)(x+7)(x-7)=0, x1=-7,x2=7 2)(5y+2)(5y-2)=0,y1=-2/5,y2=2/5 3) V R ne imeet rešenie.x1=i.5/4, x2= -i.5/4 4)(3x-5+4)(3x-5-4)=0, (3x-1)(3x-9)=0,x1=1/3,x2=3

[latex]x^2-49=0\\ x^2=49\\ x_1=-7\\ x_2=7\\\\\\ 25y^2-4=0\\ 25y^2=4\\ y^2= \frac{4}{25} \\\\ y_1= -\frac{2}{5} \\ y_2= \frac{2}{5} \\\\\\ 16x^2+25=0\\ 16x^2=-25\\ x=\varnothing\\\\\\ (3x-5)^2-16=0\\ 9x^2-30x+25-16=0\\ 9x^2-30x+9=0\ |:3\\ 3x^2-10x+3=0\\ D=100-36=64; \ \sqrt{D}=8\\\\ x_{1/2}= \frac{10\pm8}{6}\\\\ x_1= \frac{1}{3}\\\\ x_2=3 [/latex]