Решите уравнения 1/х+4-1/х-4=1/х-2-1/х-5

[latex] \frac{1}{x+4}- \frac{1}{x-4}= \frac{1}{x-2}- \frac{1}{x-5}\\x \neq -4;x \neq 2;x \neq 4;x \neq 5\\ \frac{x-4-x-4}{x^2-16} = \frac{x-5-x+2}{(x-2)(x-5)} \\\frac{-8}{x^2-16} = \frac{-3}{(x-2)(x-5)} \\-3(x^2-16)=-8(x^2-7x+10)\\3x^2-48=8x^2-56x+80\\5x^2-56x+128=0\\ \frac{D}{4} =28^2-5*128=4^2(7^2-5*8)=4^2*9=4^2*3^2=12^2\\x_1= \frac{28-12}{5} = \frac{16}{5}=3,2\\x_3= \frac{28+12}{5}= \frac{40}{5} =8[/latex]