Решите уравнения б)(1/64)^x=√1/2 в)2^x2-8x+19=16 г)lg x-4/2-x=0 Срочно нужна помощь

б)[latex] 2^{-6x} = 2^{-1/2} [/latex] -6x=-1/2 x=1/12 в)[latex] 2^{x^2-8x+19} =2^4[/latex] x²-8x+19=4 x²-8x+15=0 x1+x2=8 U x1*x2=15 x1=3 U x2=5 г)(x-4)/(2-x)>0 x=4 U x=2 x∈(2;4) (x-4)/(2-x)=1 x-4=2-x x+x=2+4 2x=6 x=3

[latex]b)\ (\frac{1}{64})^x=\sqrt{\frac{1}{2}}\\ ((\frac{1}{\sqrt2})^{12})^x=\frac{1}{\sqrt2}\\ (\frac{1}{\sqrt2})^{12x}=\frac{1}{\sqrt2}\\ 12x=1\\ x=\frac{1}{12}\\ v)\ 2^{x^2-8x+19}=16\\ 2^{x^2-8x+19}=2^4\\ x^2-8x+19=4\\ x^2-8x+15=0\\ |x=3\\ |x=5\\ g)\ \frac{lgx-4}{2-x}=0\\ x>0;\ x\neq2\\ lgx-4=0\\ lgx=4\\ lgx=lg10^4\\ x=10^4=10000\\[/latex]