Решите выражение) [latex]2x-(x+1)^2=3x^2-6[/latex]

[latex]2x-(x+1)^2=3x^2-6,\\2x-(x^2+2x+1^2)=3x^2-6,\\2x-x^2-2x-1=3x^2-6,\\-x^2-1-3x^2+6=0,\\-4x^2+5=0,\\-4x^2=-5,\\4x^2=5,\\x^2=\frac{5}{4},\\x_{1,2}=\pm\sqrt{\frac{5}{4}},\\x_{1,2}=\pm\frac{\sqrt5}{\sqrt4},\\x_{1,2}=\pm\frac{\sqrt5}{2}.[/latex] Ответ: [latex]x_{1,2}=\pm\frac{\sqrt5}{2}.[/latex]