Решите................4 задание)))

№4 [latex]x^2-2- \frac{x^2+8}{x^2+2} =0[/latex] [latex](x^2-2)- \frac{x^2+8}{x^2+2} =0[/latex]          [latex]|*(x^2+2)[/latex] [latex](x^2+2)(x^2-2)-(x^2+8)=0[/latex] [latex]x^4-4-x^2-8=0[/latex] [latex]x^4-x^2-12=0[/latex] [latex]y=x^2[/latex] [latex]y^2-y-12=0[/latex] [latex]D=b^2-4ac=(-1)^2-4*1*(-12)=1+48=49[/latex] [latex]y_1= \frac{-b+ \sqrt{D} }{2a} = \frac{1+ \sqrt{49} }{2} = \frac{1+7}{2}=4 [/latex] [latex]y_2= \frac{-b- \sqrt{D} }{2a} = \frac{1- \sqrt{49} }{2} =\frac{-6}{2} =-3[/latex] [latex]y_1=x^2_1=-3[/latex] [latex]y_2=x^2_2=4[/latex] [latex]x_2^2=4[/latex] [latex]|x=2[/latex] [latex]|x=-2[/latex] Ответ: [latex] -2[/latex]