Решить систему уравнений По подробнее

4logx+log(y+1)=6 logx+log(y+1)=6 log(x*(y+1))=6 logx+log(y+1)=2 log(x*(y+1))=2 log(x*(y+1))=log2 log(x(y+1))=log2 ОДЗ: x(y+1)>0 x>0 x>0 log(x(y+1)=log4 x(y+1)>0 x<0 x>0 x>0 y+1>0 y>-1 x(0;+) y(-1;+) x(y+1)=2 x(y+1)=64 x*(4/x)=64 4x=64 x=16 x=22 x(y+1)=4 y+1=4/x y+1=4/(22) y=2/2-1