Sin2x/sinx=0 допоможіть)

[latex] \left \{ {{sin(2x)=0} \atop {sinx \neq 0}} \right. [/latex] [latex] \left \{ {{2x= \pi k} \atop {x \neq \pi k}} \right.[/latex] [latex] \left \{ {{x=\frac{\pi k}{2}} \atop {x \neq \pi k}} \right.[/latex] Ответ: [latex]x=\frac{\pi}{2}+ \pi k[/latex],  k∈Z