(sin5x/sinx)-(cos5x/cosx)=(sinx/sin5x)-(cosx/cos5x) решите уравнение

(sin5x/sinx)-(cos5x/cosx)=(sinx/sin5x)-(cosx/cos5x)  sin5x·cosx-cos5x·sinx/sinx·cosx=sinx·cos5x-cosx·sin5x/sin5x·cos5x 2sin4x/sin2x=-2sin4x/sin10x 1/sin2x=-1/sin10x, sin2x=-sin10x sin2x+sin10x=0 sin2x+sin10x=2sin(2x+10x)/2·cos(2x-10x)/2=0 sin6x·cos4x=0 6x=πn,          4x=πn. n∈Z x=πn/6 ,        x=πn/4, n∈Z