Sinx*cos2x=0 5sin^2x=2sinx

[latex]1)sin*cos2x=0\\ sinx=0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ili \ \ \ \ \ cos2x=0\\ x=arcsin0 +\pi n, \ \ neZ \ \ \ \ \ \ \ \ \ \ \ \ \ 2x=\frac{\pi}{2}+\pi n, \ \ neZ\\ x=\pi n, \ \ neZ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=\frac{\pi}{4}+\frac{\pi n}{2}, \ \ neZ[/latex] [latex]2) 5sin^2x=2sinx\\ \frac{5sin^2x}{sinx}=2\\ 5sinx=2\\ sinx=\frac25\\ x=(-1)^n arcsin\frac25+\pi n, \ \ neZ[/latex]