Система уравнени x²-y+xy=x; 2x²+y²=12

[latex] \left \{ {{x^2-y+xy=x} \atop {2x^2+y^2=12}} \right. \; \left \{ {{x(x+y)-(x+y)=0} \atop {2x^2+y^2=12}} \right. \; \left \{ {{(x+y)(x-1)=0} \atop {2x^2+y^2=12}} \right. \\\\1)\; \left \{ {{x+y=0,\to y=-x} \atop {2x^2+(-x)^2=12}} \right. \; \left \{ {{y=-x} \atop {3x^2=12}} \right. \; \left \{ {{y=-x} \atop {x^2=4}} \right. \; \left \{ {{y_1=-2,\; y_2=2} \atop {x_1=2,\; x_2=-2}} \right. \; \Rightarrow \; (2,-2),\; (-2,2)\\\\2)\; \left \{ {{x=1} \atop {2+y^2=12}} \right. [/latex] [latex] \left \{ {{x=1} \atop {y^2=10}} \right. \; \left \{ {{x=1} \atop {y=\pm \sqrt{10}}} \right. \; \Rightarrow \; (1,\sqrt{10}),\; (1.-\sqrt{10}).[/latex]